b^4+2b^2-8=0

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Solution for b^4+2b^2-8=0 equation:


Simplifying
b4 + 2b2 + -8 = 0

Reorder the terms:
-8 + 2b2 + b4 = 0

Solving
-8 + 2b2 + b4 = 0

Solving for variable 'b'.

Factor a trinomial.
(-4 + -1b2)(2 + -1b2) = 0

Subproblem 1

Set the factor '(-4 + -1b2)' equal to zero and attempt to solve: Simplifying -4 + -1b2 = 0 Solving -4 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b2 = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b2 = 0 + 4 -1b2 = 0 + 4 Combine like terms: 0 + 4 = 4 -1b2 = 4 Divide each side by '-1'. b2 = -4 Simplifying b2 = -4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + -1b2)' equal to zero and attempt to solve: Simplifying 2 + -1b2 = 0 Solving 2 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b2 = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b2 = 0 + -2 -1b2 = 0 + -2 Combine like terms: 0 + -2 = -2 -1b2 = -2 Divide each side by '-1'. b2 = 2 Simplifying b2 = 2 Take the square root of each side: b = {-1.414213562, 1.414213562}

Solution

b = {-1.414213562, 1.414213562}

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